(p^3-4p^2+p)-(3p^2+2p+7)=0

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Solution for (p^3-4p^2+p)-(3p^2+2p+7)=0 equation: 


Simplifying
(p3 + -4p2 + p) + -1(3p2 + 2p + 7) = 0

Reorder the terms:
(p + -4p2 + p3) + -1(3p2 + 2p + 7) = 0

Remove parenthesis around (p + -4p2 + p3)
p + -4p2 + p3 + -1(3p2 + 2p + 7) = 0

Reorder the terms:
p + -4p2 + p3 + -1(7 + 2p + 3p2) = 0
p + -4p2 + p3 + (7 * -1 + 2p * -1 + 3p2 * -1) = 0
p + -4p2 + p3 + (-7 + -2p + -3p2) = 0

Reorder the terms:
-7 + p + -2p + -4p2 + -3p2 + p3 = 0

Combine like terms: p + -2p = -1p
-7 + -1p + -4p2 + -3p2 + p3 = 0

Combine like terms: -4p2 + -3p2 = -7p2
-7 + -1p + -7p2 + p3 = 0

Solving
-7 + -1p + -7p2 + p3 = 0

Solving for variable 'p'.

The solution to this equation could not be determined.

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